Operation Manual

<13. GENERAL SPECIFICATIONS>
13-18
IM 01F06A00-01EN
 Reference
Table 13.11 Inner Diameter and Nominal value
Model Code
Inner
Diameter
mm
Nominal
K-Factor
Pulse/L
Nominal Pulse
Rate
Hz / m/s Hz / m
3
/h
DY015
DY025
/R1
DY040
/R2
14.6 376 62.7 104
DY025
DY040
/R1
DY050
/R2
25.7 68.6 35.5 19.1
DY040
DY050
/R1
DY080
/R2
39.7 18.7 23.1 5.19
DY050
DY080
/R1
DY100
/R2
51.1 8.95 18.3 2.49
DY080
DY100
/R1
DY150
/R2
71.0 3.33 13.2 0.925
DY100
DY150
/R1
DY200
/R2
93.8 1.43 9.88 0.397
DY150
DY200
/R1
— 138.8 0.441 6.67 0.123
DY200 — — 185.6 0.185 5.00 0.0514
DY250 — — 230.8 0.0966 4.04 0.0268
DY300 — — 276.2 0.0563 3.37 0.0156
DY400 — — 354.2 0.0265 2.61 0.00736
 Pressure Loss
Calculation of pressure loss for standard type
obtained from the following equations.
P=108×10
5
×
f
×
2
······ (1)
or
P=135×
f
×
Q
f
2
D
4
········· (2)
where,
P: Pressure loss (kPa )

f
: Density at operating condition (kg/m
3
)
: Flow velocity (m/s)
Q
f
: Actual fl ow rate (m
3
/h)
D: Inner diameter of digitalYEWFLO (mm)
(Example)
DY050, hot water: 80°C, fl owrate: 30 m
3
/h
1. Since the density of water at 80°C is 972 kg/
m
3
, substitute this value in equation (2):
P = 135 × 972 × 30
2
/ 51.1
4
= 17.3 kPa
2. Obtain the pressure loss using equation (1).
The fl ow velocity when the fl ow rate is 30 m
3
/h
is given by:
 = 354×Q
f
/D
2
=
354×30
51.1
2
= 4.07m/s
Therefore, substitute this value in equation (1):
P = 108 × 10
-5
× 972 × 4.07
2
= 17.3 kPa
Calculation of pressure loss for reduced bore
type (Option code: /R1)
obtained from the following equations.
P = 124 × 10
-5
× 
f
× 
2
··········· (3)
or
P = 155 × 
f
× Q
f
2
/ D
4
············ (4)
(Example)
DY040/R1, hot water: 50 °C, fl owrate: 10 m
3
/h
1. Since the density of water at 50 °C is 992 kg/
m
3
, substitute this value in equation (4):
P = 155 × 992 × 10
2
/ 25.7
4
= 35.3 kPa
2. Obtain by using equation (3). The fl ow velocity
when the fl ow rate is 10 m
3
/h is given by:
 = 354 × Q
f
× /D
2
= 354 × 10 × 25.7
2
= 5.4m/s
Therefore, substitute this value in equation (3):
P = 124 × 10
-5
× 992 × 5.4
2
= 35.3 kPa
Calculation of pressure loss for reduced bore
type (Option code: /R2)
obtained from the following equations.
P = 138 × 10
-5
× 
f
× 
2
··········· (5)
or
P = 173 × 
f
×
Q
f
2
D
4
················ (6)
(Example)
DY050-/R2, hot water: 50 °C, fl owrate: 15 m
3
/h
1. Since the density of water at 50 °C is 992 kg/
m
3
, substitute this value in equation (6):
P = 173 × 992 × 15
2
/ 25.7
4
= 88.5 kPa
2. Obtain by using equation (5). The fl ow velocity
when the fl ow rate is 15m
3
/h is given by:
 = 354×Q
f
/D
2
=
354×15
25.7
2
= 8.0m/s
Therefore, substitute this value in equation (5):
P = 138 × 10
-5
× 992 × 8.0
2
= 88.5 kPa