Specifications

Lab 5: Phase Locked Loop
Solutions
la) Q: Use the following equations to determine f
0
, f
c
, and f, for V
cc
= ±10 volts.
Component values can be found on fig 1.
fa
1.2
4*A
//
8/
0
T = 3.6xl0
3
C,
c
2%\
2nf,
A: ¥„ = ±10
64xl0
3
= —
4(Ä
1
).001xlO~
*R
t
= 4.688xl0
3
Q
(8X64x10^
= 51
_
2rlo3fl
.
10
x - (3.6x10
3
X-1*10 ■ *) - .36*10 ~
3
fc
2«(51.2x10")
2n\ .36x10
-3
= 4751 Hz
Measured values for: R
x
= 4.67 kQ , C
t
= 1.065 x 10'
9
, C,= 100.2 x 10'
9
Lab 5 Solutions Page 1
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