Extra Information
FRESHWATER
COOLING
2002,
2003
Pos
21
and23
are
for
hot
water
outlet
.
1
.
Fit
the
circulation
pump
(complete
with
tensioner
bracket
and
spacer
sleeve,
position
4)
.
Tighten
the
bolts
(M8x75)
to
20
Nm
(2,0
kpm)
(14
.7
ft
.lbs),
position
1
.
2
.
Suspend
the
heat
exchanger
loosely
by
the
rear bolt
(M8x16and
spring
washer
.),
position
5
.
a)
Fit
the
pipe
(position
6)
and the
hose
(position
3)
between
the
heat
exchanger
and the
sea-water
pump, using
double
hoseclamps
(apply
soapy
water
to
the
rubber
rings,
applies
for
all
rubber
rings)
.
b)
Fit
the
pipe
between
the
heat-exchanger
and
thermostat
housing,
position
7
.
c)
Fit
the
pipe
between
the
heat-exchanger
and
the
circulation
pump,
position
8
.
3
.
Locatethe
pipes
in
the
heat-exchanger
andanddraw
it
forward
tightening
it
with
the
two
bolts
(M8x16and
spring
washers),
positions
5and
9
.
4
.
Fit
the
pipe
between
the
heat-exchanger
and
the
exhaust
elbow,
position
10
.
NOTE!
The
holderforthe
pipe, (position
11)
and
the
lock (position
11
a)
.
5
.
Fit
the
pipe
between
the
circulation
pump
(lower
outlet)
and
the
cylinder
head,
position
12
.
6
.
Fit
the
pipe
between
the
circulation
pump
(upper
outlet)
and
the
cylinder
head,
position
13
.
7
.
Fit
the
alternator,
place
the
bolt
for
the tensioner
bracket
with
the
head
forwards
.
Put
onand
tension
the
V-belt
.
8
.
Fit
the
expansion
tank
to
the
exhaust
elbow,
position
15
.
9
.
Fit
the
hose
between
the
tank
and
the
circulation
pump
(double
pipe
)
2002
=
450
mm
(17
.7
in),
2003
=
550
mm
(21
.7
in)
(only single
hose
clamps
are
used
on
the
fresh-watersystem),
position
16
.
10
.
Fit
the
nipple,
position
17
.
11
.
Fitthe
hose
between
the
tank
and
the
thermostat
housing
(nipple 17)
:
2002
=
350
mm
(13
.8
in),
2003
=
450
mm
(17
.7
in),
position
18
.
12
.
Fit
the
plugs
in
the
exhaust
elbowand
the
cylinder
head,
positions
19
and
20
.
13
.
Fill
the
system
to
the
right
level
with
a
mixture
of
fresh
water
(50%
)
and
anti-freeze
(50%),
altematively
rust-protection
additive
(VP
accessory)
. The
fresh-water
system volumes
:
2002 = 4.0 dm2
(litre)
(0.88 Imp.
gals)
(1.1 US gals),
2003
=
5
.5
dm
3
(litre) (1
.2
Imp
.
gals)
(1
.45
US
gals)
.