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Electrical Characteristics for 5-V Supply
(1)
TS5A4624
1- Ω SPDT ANALOG SWITCH
5-V/3.3-V SINGLE-CHANNEL 2:1 MULTIPLEXER/DEMULTIPLEXER
SLYS014A – DECEMBER 2005 – REVISED AUGUST 2006
V
+
= 4.5 V to 5.5 V, T
A
= –40 ° C to 85 ° C (unless otherwise noted)
PARAMETER SYMBOL TEST CONDITIONS T
A
V
+
MIN TYP MAX UNIT
Analog Switch
Analog signal V
COM
, V
NO
,
0 V
+
V
range V
NC
25 ° C 0.8 1.1
Peak ON 0 ≤ (V
NO
or V
NC
) ≤ V
+
, Switch ON,
r
peak
4.5 V Ω
resistance I
COM
= –100 mA, See Figure 13
Full 1.5
25 ° C 0.7 0.9
ON-state V
NO
or V
NC
= 2.5 V, Switch ON,
r
on
4.5 V Ω
resistance I
COM
= –100 mA, See Figure 13
Full 1.1
ON-state 25 ° C 0.05 0.1
resistance
V
NO
or V
NC
= 2.5 V, Switch ON,
match ∆ r
on
4.5 V Ω
I
COM
= –100 mA, See Figure 13
Full 0.1
between
channels
0 ≤ (V
NO
or V
NC
) ≤ V
+
, Switch ON,
25 ° C 0.15
ON-state
I
COM
= –100 mA, See Figure 13
resistance r
on(flat)
4.5 V Ω
25 ° C 0.1 0.25
V
NO
or V
NC
= 1 V, 1.5 V, 2.5 V, Switch ON,
flatness
I
COM
= –100 mA, See Figure 13
Full 0.25
V
NC
or V
NO
= 1 V, 25 ° C –20 2 20
V
COM
= 1 V to 4.5 V,
I
NC(OFF)
, Switch OFF,
or 5.5 V nA
NC, NO
I
NO(OFF)
See Figure 14
Full –100 100
V
NC
or V
NO
= 4.5 V,
OFF leakage
V
COM
= 1 V to 4.5 V,
current
25 ° C –1 0.2 1
I
NC(PWROFF)
, V
NC
or V
NO
= 0 to 5.5 V, Switch OFF,
0 V µ A
I
NO(PWROFF)
V
COM
= 5.5 V to 0, See Figure 14
Full –20 20
NC, NO V
NC
or V
NO
= 1 V, V
COM
= Open, 25 ° C –20 2 20
I
NC(ON)
, Switch ON,
ON leakage or 5.5 V nA
I
NO(ON)
See Figure 15
Full –100 100
current V
NC
or V
NO
= 4.5 V, V
COM
= Open,
COM 25 ° –1 0.1 1
V
NC
or V
NO
= 0 to 5.5 V, Switch OFF,
OFF leakage I
COM(PWROFF)
0 V µ A
V
COM
= 5.5 V to 0, See Figure 14
Full –20 20
current
COM V
NC
or V
NO
= Open, V
COM
= 1 V, 25 ° C –20 2 20
Switch ON,
ON leakage I
COM(ON)
or 5.5 V nA
See Figure 15
Full –100 100
current V
NC
or V
NO
= Open, V
COM
= 4.5 V,
Digital Input (IN)
Input logic high V
IH
Full 2.4 5.5 V
Input logic low V
IL
Full 0 0.8 V
25 ° C 5.5 V –2 2
Input leakage
I
IH
, I
IL
V
I
= 5.5 V or 0 nA
current
Full 100 100
(1) The algebraic convention, whereby the most negative value is a minimum and the most positive value is a maximum
4
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