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R11 = 15.8 k:
R18 = 750 k:
=
V
OFFTURN
=
-
V= 40
R11
k8.15 :
( )
k750k8.151.24V :+:x
(
)
R18
R11
1.24V +x
V
OFFTURN-
:== k15.8
-
-
1.24VV
OFFTURN
x R181.24V
=R11
:x k7501.24V
-1.24V60V
15VA20k750A20
R18
V
HYSO
=
x:
=
x
=
P
P
===
A
20
15V
R18
P
:k750
V
HYSO
A20
P
k:10R13
=
k:1.43R5
=
k:16.9R4
=
V
HYS
=
R5
20 PA x 16.9 k: x (1.43 k: + 10 k:)
1.43 k:
V
HYS
=
+ 20 PA x R
UV2
20 PA x R4 x (R5 + R13)
+ 20 PA x 10 k: = 2.9V
=
16.9 k:
=
20 PA x (1.43 k: + 10 k:)
R4
=
R4
(
)
R5 xx R13
V
HYS
- 20 PA
R5
R13+
(
)
20 PA
x
(
:
)
x k10k1.43
2.9V - 20 PA
: x
R5
(
)
R13R51.24V +x
V
ONTURN
=
-
= V9.91=
( )
k10k1.431.24V :+:x
k1.43 :
V
ONTURN-
:== k1.43
-
-
1.24VV
ONTURN
x R131.24V
=
R5
:x k101.24V
-1.24V10V
Design Procedure
www.ti.com
(45)
The closest standard resistor is 1.43 k therefore V
TURN-ON
is:
(46)
Solve for R4:
(47)
The closest standard resistor is 16.9 k making V
HYS
:
(48)
The chosen components from step 11 are:
(49)
6.13 Output OVLO
Solve for R18:
(50)
The closest standard resistor is 750 k therefore V
HYSO
is:
(51)
Solve for R11:
(52)
The closest standard resistor is 15.8 k making V
TURN-OFF
:
(53)
The chosen components from step 12 are:
(54)
10
AN-1986 LM3429 Boost Evaluation Board SNVA404BJuly 2009Revised May 2013
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