Datasheet

0 6 10
30
40
V
IN
(V)
20
FREQUENCY (kHz)
250
200
150
100
50
Load Current = 500 mA
200 400 600 800 1000
LOAD CURRENT (mA)
90
80
70
60
50
100
EFFICIENCY (%)
V
IN
= 6V
12V
40V
LM25010
www.ti.com SNVS419D –DECEMBER 2005–REVISED FEBRUARY 2013
ITEM DESCRIPTION VALUE
C5 Ceramic Capacitor 0.1 µF, 50V
D1 Schottky Diode 60V, 2A
L1 Inductor 100 µH
R1 Resistor 1.0 kΩ
R2 Resistor 1.0 kΩ
R3 Resistor 1.5 Ω
R
ON
Resistor 200 kΩ
U1 LM25010
Figure 13. Efficiency vs Load Current and V
IN
Circuit of Figure 12
Figure 14. Frequency vs V
IN
Circuit of Figure 12
Minimum Load Current
The LM25010 requires a minimum load current of 500 µA. If the load current falls below that level, the bootstrap
capacitor (C4) may discharge during the long off-time, and the circuit will either shutdown, or cycle on and off at
a low frequency. If the load current is expected to drop below 500 µA in the application, R1 and R2 should be
chosen low enough in value so they provide the minimum required current at nominal V
OUT
.
Low Output Ripple Configurations
For applications where low output voltage ripple is required the output can be taken directly from the low ESR
output capacitor (C2) as shown in Figure 15. However, R3 slightly degrades the load regulation. The specific
component values, and the application determine if this is suitable.
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