Datasheet

Application information L7986TA
26/43 Doc ID 022098 Rev 3
4. Then calculate C
3
in order to place the second pole at four times the system bandwidth
(BW):
Equation 33
For example, with V
OUT
=5 V, V
IN
=24 V, I
O
=3 A, L=18 μH, C
OUT
=330 μF, and ESR=35 mΩ,
the type II compensation network is:
Equation 34
In Figure 14 the module and phase of the open-loop gain is shown. The bandwidth is about
21 kHz and the phase margin is 45 °.
C
5
C
4
2π R
4
C
4
4BW⋅ 1–⋅⋅⋅
-------------------------------------------------------------------------=
R
1
1.1kΩ= R
2
150Ω= R
4
4.99kΩ= C
4
82nF= C
5
68pF=,, ,,