Brochure
∆
P = 0.18 MPa
∆
P = 0.1 MPa
∆
P = 0.35 MPa
∆P = 0.25 MPa
PVQ30
(ø2.3)
120
100
80
60
40
20
0
0
0
20
40
40
80
60
120
80
160
100
200
120
240
140
280
160
320
180
360
200
400
Current (mA)
Flow rate (l/min)
24 VDC →
12 VDC →
∆
P = 0.06 MPa
∆
P = 0.04 MPa
∆
P = 0.12 MPa
∆P = 0.08 MPa
PVQ30
(ø4.0)
120
100
80
60
40
20
0
0
0
20
40
40
80
60
120
80
160
100
200
120
240
140
280
160
320
180
360
200
400
Current (mA)
Flow rate (l/min)
24 VDC →
12 VDC →
∆P = 0.7 MPa
∆P = 0.5 MPa
∆P = 0.35 MPa
∆
P = 0.2 MPa
PVQ30
(ø1.6)
120
100
80
60
40
20
0
0
0
20
40
40
80
60
120
80
160
100
200
120
240
140
280
160
320
180
360
200
400
Current (mA)
Flow rate (l/min)
24 VDC →
12 VDC →
Q. Required flow rate = 0 to 75 l/min.
In this case, all of PVQ30 series orifice sizes satisfy the required flow rate. (Flow rate when rated current is applied)
The table below shows the pressure differentials needed to satisfy the required flow rate. In the flow rate characte-
ristic charts, a pressure differential over the flow rate indicated by the dashed line (75 l/min.) up to the max. opera-
ting pressure differential will satisfy the required flow rate.
P1 = No conditions, P2 = 0 MPa (Atmospheric pressure)
Table. Pressure differential needed to satisfy the required flow rate = 0 to 75 l/min.
Note
ø1.6
0.5 to 0.7 MPa
Pressure differential (∆P)
ø2.3
0.25 to 0.35 MPa
ø4.0
0.12 MPa
1) Follow the same procedure for selecting PVQ10 series.
2) Flow rate depends on individual differences between valves and piping conditions. Refer to the flow characteristic
chart to select the model with adequate margin for the required flow rate.
∆P = (P1 – P2) MPa
∆P: Pressure differential
P1 : Inlet pressure
P2 : Outlet pressure
Model Selection
• For vacuum specifications, the operating pressure range is from 0.1 Pa·abs to max. operating pressure differential.
• A(2) port is applicable with vacuum pressure.
<To use orifice ø1.6 (See PVQ30: Chart 1)>
Condition 1. P1 = 0.7 MPa, P2 = 0 MPa (Atmospheric pressure)
Ex) At increasing currents, when a 140 mA current is applied, a flow rate of 85 l/min is achieved. (See
q
.)
If current decreases at this point, the flow rate may not change by 135 mA due to hysteresis. (See
w
.)
The flow rate at an increasing and decreasing current is not the same due to hysteresis. (
q
85
l/min.,
e
93
l/min.)
Refer to curve A when ∆P is 0.7 MPa.
Condition 2. P1 = 0.7 MPa, P2 = 0.2 MPa
Condition 3. Under vacuum pressure
Ex) At increasing currents, when a 150 mA current is applied, a flow rate of 65 l/min is achieved. (See
r
.)
If P2 increases by 0.15 MPa, ∆P decreases by 0.15 MPa and becomes 0.35 MPa (See curve C), and when the
same current is applied the flow rate is 40
l/min. (See
t
.)
• The flow rate decreases due to a change (increase) in the outlet pressure, even if the inlet pressure and the
current value are the same.
Refer to curve B when ∆P is 0.5 MPa.
∆P = (P
1
– P
2
) MPa
∆P: Pressure differential
P
1
: Inlet pressure
P
2
: Outlet pressure
<Chart 1> PVQ30 (ø1.6)
t
r
q
e
w
Decreasing current
Increasing
current
Curve A
∆P = 0.7 MPa
Curve
B
∆
P = 0.5 MPa
120
100
80
60
40
20
0
0
0
20
40
40
80
60
120
80
160
100
200
120
240
140
280
160
320
180
360
200
400
Current (mA)
Flow rate (l/min)
24 VDC →
12 VDC →
Curve
D
∆
P = 0.2 MPa
Curve C
∆P = 0.35 MPa
Series
PVQ
Model Selection
Front matter 2