User`s manual

DeviceNet (Master) Function
8-22
8
Address *
1st byte (2000)
2nd byte (2001)
3rd byte (2002)
4th byte (2003)
5th byte (2004)
6th byte (2005)
7th byte (2006)
8th byte (2007)
9th byte (2010)
10th byte (2011)
11th byte (2012)
12th byte (2013)
to
512th byte (2777)
Input/output data table
1sserddaedoN
)noitatsevals(
tupnI
tuptuO
3sserddaedoN
)noitatsevals(
tupnI
tuptuO
5sserddaedoN
)noitatsevals(
tupnI
desutoN
* Addresses in parentheses are correct
when the data table allocation system is
set to "fixed allocation."
sserddaedoN )setyb(htgnelatadderiuqeR
egassemO/I
noitcnuf
)setyb(htgnelataddengissA
1)tuptuo1,tupni1(2seY
)tuptuo1,tupni1(2
2detcennoctoN-
0
3)tuptuo3,tupni3(6seY
)tuptuo3,tupni3(6
40 oN
0
5)tuptuo0,tupni3(3seY
)tupni3(3
- The required number of bytes are assigned to the slaves at nodes 1, 3, and 5.
- Slave 2 (nothing connected) and slave 4 (doesn't have a I/O message function) are not
assigned any data length.
Three allocation examples are shown below.
- Node address 0 : The JW-32CUM1 (master)
- Node address 1 : Slave station Polling I/O input data = 1 byte
Polling I/O output data = 1 byte
- Node address 2 : Not connected
- Node address 3 : Slave station Polling I/O input data = 3 bytes
Polling I/O output data = 3 bytes
- Node address 4 : Slave station (No I/O message function)
- Node address 5 : Slave station Polling I/O input data = 3 bytes
Polling I/O output data = 0 byte
(1) Address order allocation
Assign the number of bytes of data in the input/output data table (data length) in the same order as the
node addresses are assigned to the slave stations.
1. Assign the number of bytes required by each slave station.
2. A slave station that does not have I/O message function is not assigned a data length.
3. Any slave station number (node address), that does not have hardware connected, is not assigned
a data length.
Allocation example
The allocation results from assigning data lengths "in the order in which vacant nodes are
occupied" are as follows: