Specifications

2–28
Selecting Your Hardware Components
Publication
1747-6.2
To reduce the possibility of inadvertent operation of devices
connected to transistor outputs, adhere to the following guidelines:
Either ensure that any programmable device connected to the
transistor output is programmed to ignore all output signals until
after the transient pulse has ended,
or add an external resistor in parallel to the load to increase the
on-state load current. The duration of the transient pulse is
reduced when the on-state load current is increased.
The duration of the transient pulse is proportional to the load
impedance. This is illustrated in the following graph.
0
On-State Load Current (mA)
1000
1
2
3
4
5
6
7
8
9
10
1 100 200
300
400 500 600 700 800 900
Duration of Transient (ms)
Time
Example
Increasing the load current by 100 mA decreases the transient time
from approximately 7 ms to less than 2.5 ms. To calculate the size of
the resistor added in parallel to increase the current, use the
following information:
R (Ohms)
V (Volts)
I (Amps)
Resistor value (Ohms) = Applied voltage (Volts) / Desired current (Amps)
= 24 / 0.1 = 240 (Ohms)
P (Watts) = I
2
(Amps) x R (Ohms)
Actual Power (Watts) = (Desired Current)
2
x Resistor Value
Resistor size = 2 x Actual power (Watts) = 4.8W 5W
=
24V = your applied voltage
Need 100 mA of load current to reduce the transient to < 2.5 ms. (taken from graph above)
= (0.1)
2
x 240 = 2.4 (Watts)
Use a resistor rated for 240 Ohms at 5 Watts to decrease the transient
time from approximately 7 ms to less than 2.5 ms.