Specifications

Event Multitasking - 14

Timer 0 is configured at address 0 and bit 1. The wait time is 0.05 seconds. The output will go high for 0.06 seconds at

the end of the wait period, and then go low.

The PULSE function returns the remaining time of each stage. If the return is negative, the number is the time left in the

wait stage. If the return is positive, the number is the remaining part of the active time. The example below demonstrates

this.

10 PULSE 0,0,1,.05,1

30 A = PULSE(0):IF A=0 THEN STOP

40 PRINT A

50 GOTO 30

RUN

–.05

–.045

.03

.02

.01

5E-03

STOP

Operation of a Multiple Pulsed Outputs

The real power of the PULSE operation comes when multiple timed outputs are required and the time relationship between

outputs must be maintained. The application could involve pneumatic valves, injection molding steps or other

sequence–oriented operations.

10 PULSE 0,0,0,4,1

20 PULSE 1,0,1,6.5,1

30 PULSE 2,0,2,1.5,1

40 PULSE 3,0,3,7.5,1

50 .

60 .

The rest of your program, starting at line 60, executes independently of the timed outputs. Each output will time without

further intervention by the program. Thus, the program can do other tasks, like handle communications, check safety limits

and acquire process data such as temperatures, pressures, etc.

If the program should terminate before a timer times out, the bit will be left in the “active” state. When program execution

stops, all timers are cancelled. If the program is restarted with the CONT statement, the timers will not restart.