manual

QuickNet Application Guide
12
Example:
– In-cabinet length = 66 in. (24 in. + 28 in. + 14 in.)
A1 – Horizontal distance along patch panel = 24 in.
A2 – Horizontal distance from panel to cable entry/exit point = 28 in.
A3 – Vertical distance from panel to cable entry/exit point = 14 in. (8 x 1.75 in.), assuming panel is 8 RU
from cabinet top.
– Cabinet-to-pathway length = 1 ft.
– Length along pathway = 16.5 ft. (assuming seven 24 in. wide server cabinets and cable exit on far side of 30 in.
wide network cabinet = (7 x 2 ft.) + 30 in)
– Pathway-to-cabinet length = 1 ft.
– In-cabinet length = 80 in. (24 in. + 28 in. + 28 in., same as A above but with panel at 16 RU from cabinet top
so E3 = 28 in.)
– Buffer length = 2 ft.
Slack length = none for this example
Total length = (A+B+C+D+E+F) = (66 in.+1 ft.+16.5 ft.+1 ft.+80 in.+2 ft.) = 32 ft. 8 in., round up to 33 ft.
Length Measurement Example
A
B
C
D
E
F
A
B
C
D
E
F
24 in.
28 in.
66 in.
14 in.
28 in.
28 in.
24 in.
80 in.
2 ft.
1 ft.
1 ft.
16.5 ft.
Total length = 33 ft.
Tips for Measuring Lengths:
• The specified length of a QuickNet
™
Cable Assembly is the distance as measured from the front of the connector
on one end to the front of the connector on the other end. Other than a nominal manufacturing tolerance there is
no additional length built into a QuickNet
™
Cable Assembly.
• Remember to account for any turns or obstructions in the pathway that may lead to additional length needed (for
example, ducting, support posts, etc.).
• Cable assembly bend radius limits must be taken into consideration, especially for multiple turns within cabinets
or as the cable assembly transitions to or from the pathways, and may require additional length of the assembly.