1.5

Table Of Contents

var labelElm = loadhtml('snippets/label.html');

var labelStr = "";

for( var i = 0; i < record.tables.products.length); i++) {

var label = labelElm.clone();

label.find('@ProductLabel@').text(record.tables.products

[i].ProductDescription);

labelStr += label;

}

results.after(labelStr);

Use replace()

When personalizing HTML fragments retrieved from a snippet or from the template itself,

JavaScript's replace() method shows the best performance.

Replace() can only be used on Strings, while the commands loadhtml() and query() return or a

QueryResult, which is a set of strings, like the results object.

A QueryResult allows you to perform DOM manipulations like adding and removing elements,

adding and removing CSS classes etc. When the required manipulations are limited to

find/replace actions, you could change the QueryResult into a string. This allows you to replace

text using the replace() method.

For this, you could use toString():

var labelSnippet = loadhtml('snippets/label.html').toString();

Or you could copy the HTML of the QueryResults to a variable:

var block = results.html();

Example

var labelSnippet = loadhtml('snippets/label.html').toString();

var labelStr = "";

for( var i = 0; i < record.tables.detail.length; i++) {

var label = labelSnippet;

label = label.replace('#', i);

label = label.replace('@product@', record.tables.detail[i].fields

['product']);

label = label.replace('@notes@', record.tables.detail[i].fields

['notes']);

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