Instruction manual

Page 1114 of 3156 CLASS: Calling Number and Name Delivery
553-3001-306 Standard 10.00 January 2002
2Example 2: Re-configuration
A similar application as in the last example, except that there are 1600
non-CLASS sets and 100 trunks in group 1.
Solution:
The same number of CMOD units (10), since the number of CLASS sets
in the system is the same.
The number of total equivalent sets in group 1 is 2300 (=1600 +300
+100x4) which is greater than the 1760 threshold in the Table 38 for a 2-
group system.
The customer will have a number of alternatives to resolve the junctor
blocking issue, depending on the situation:
(1) move the 100 CLASS sets from group 0 to group 1, so all CLASS sets
are served by the XCMC pack in group 1, or
(2) move the 300 CLASS sets and the XCMC pack to group 0, or
(3) move 540 non-CLASS sets (=2300-1760) from group 1 to group 0, or
(4) move 100 CLASS sets from group 1 to group 0 and split the 10
CMOD units to 5 for group 0 and 5 for group 1. However, this will
require another XCMC pack to be equipped in group 0. The cost of this
approach is not trivial. It can be justified only when growth plan indicates
a need for a second pack in the near future anyway.
The final decision depends on the specific situation of a site.
Call Center applications
Configurations following engineering rules (no re-configuration
required)
The following engineering rules should be followed to avoid the need to re-
configure a switch to accommodate the CLASS feature for call center
environment.
1 Convert an agent set to regular set by using 1 agent CLASS set = 4 sets
(called equivalent sets)
2 Sum up the total number of regular CLASS sets and equivalent CLASS
sets and find the number of CMOD units required based on the capacity
table (Table 39).