User's Manual
Design
P/N 81-CO2MAN-001 3-21 September 2013
3-5.3.2.1 Uncloseable Openings
Any openings in the enclosure that either do not border the ceiling or are not in the ceiling itself
and cannot be closed at the time of suppression must be compensated for by additional carbon
dioxide equal to the expected leakage rate during the suppression period. The method
specified in Paragraph 3-5.2.4.1 shall be used to calculate the additional carbon dioxide
quantity. An extended discharge may be required to maintain the concentration for the
designed duration of protection, lasting at least 20 minutes (See Paragraph 3-10).
3-5.3.2.2 Forced Ventilation
Additional carbon dioxide must be provided to compensate for a forced air ventilating system
that cannot be shut off or dampered prior to or at the start of discharge. The method described
in Paragraph 3-5.2.4.2 shall be used to calculate the additional carbon dioxide quantity. An
extended discharge may be necessary to ensure the maintenance of the suppression
concentration for the designed duration of protection, lasting at least 20 minutes (See
Paragraph 3-10).
3-5.3.2.3 Extreme Temperatures
Additional carbon dioxide is required to compensate for abnormally low or high ambient
temperatures in the protected area. The additional quantity shall be calculated using the
methods described in Paragraph 3-5.2.4.3.
3-5.3.3 DISCHARGE RATES
For deep-seated fires, the design concentration shall be achieved within 7 minutes, but the rate
shall not be less than required to develop a concentration of 30% within 2 minutes.
As a guide, the quantity of carbon dioxide required to achieve a 30% concentration is 0.0428
lb./
ft.
3
(0.686 kg/m
3
) (See Appendix A-5). Equation (13) may be used to calculate the
discharge rate required to achieve this concentration within 2 minutes.
(Equation 13)
(US Units)
or
(Metric Units)
Where:
= Minimum flow rate to achieve a 30% concentration within minutes,
lb./min (kg/min)
= Enclosure volume,
ft.
3
(m
3
)
Perform a check to ensure that the discharge will be complete within seven (7) minutes.
(Equation 14)
Where:
= Discharge time, min
= Minimum quantity of agent to be supplied from Equation (3), lb.(kg)
= Flow rate from Equation (13), lb./min (kg/min)
q
30
0.0214 V=
q
30
0.343 V=
q
30
V
t
d
W
min
q
30
=
t
d
W
min
q
30