User's Manual

Design
September 2013 3-18 P/N 81-CO2MAN-001
EXAMPLE 6 - TOTAL FLOODING FOR SURFACE FIRES - Discharge Rate
Consider a room with dimensions of 20 ft. (L) by 30 ft. (W) by 10 ft. (H). Determine the minimum
flow rate required to create a 34% by volume concentration within the acceptable time limit.
From Equation (11):
Where is the Minimum Discharge Rate, is the Minimum Agent Quantity, and is the
Maximum Discharge Time.
From Equation (3):
Where is the Quantity of Agent for the Design Concentration, is the Quantity of Agent to
Compensate for Leakage, is the Quantity of Agent to Compensate for Ventilation, and is
the Quantity of Agent to Compensate for Extreme Temperatures.
Equation (2):
Where is the Basic Quantity (34%) and is the Material Conversion Factor.
From Equation (1):
Where is Volume Of The Protected Space and is the Volume Factor.
= 20 ft. x 30 ft. x 10 ft.
= 6,000
ft.
3
= 20 ft.
3
/lb. from Table 3-2 for volumes 4,501 ft.
3
to 50,000 ft.
3
.
= 6,000  20
= 300 lb.
= 1.0, from Figure 3-1 for 34% concentration
= 300 X 1.0
= 300 lb.
= 0 lb.
= 0 lb.
= 0 lb.
= 300 + 0 + 0 + 0
= 300 lb.
= 
= 300  1
= 300 lb./min
q
min
W
min
t
dmax
=
q
min
Wmin
t
dmax
W
min
W
C
W
L
W
V
W
T
+++=
W
C
W
L
W
V
W
T
W
C
W
B
f
C
=
W
B
f
c
W
B
Vf
1
=
V
f
1
V
V
f
1
W
B
Vf
1
=
W
B
W
B
f
c
W
C
W
B
f
C
=
W
C
W
C
W
L
W
V
W
T
W
min
W
C
W
L
W
V
W
T
+++=
Wmin
Wmin
q
min
Wmin
t
dmax
q
min
q
min