Use Instructions

269
Understanding Insulin Delivery and Calculations23
Example 3
No carbs entered, used CGM of 180 mg/dL with decreasing trend. ere is 0.8 U
meal IOB and 0.5 U correction IOB from previous meal and correction boluses.
Correction Bolus
0 U
Your glucose is 180 mg/dL,
which is 50 mg/dL over target.
Because your correction factor
is 50, the initial correction bolus
is 1 U.
CGM = 180, Target BG = 130
Correction Factor = 50
(180 -130) / 50 = 1 U
Meal IOB adjustment
Meal IOB = 0.8 U
1 U - 0.8 U = 0.2 U
Since you have 0.8 U of meal
IOB remaining from a previous
meal bolus, this is subtracted
from the initial correction bolus
of 1 U, and you have 0.2 U of
correction bolus remaining.
You also have 0.5 U of
correction IOB from previous
insulin action. This is subtracted
from the remaining correction
bolus of 0.2 U, driving the nal
calculated correction bolus to 0
U. Note that 0.3 U of correction
IOB still remains after driving
correction bolus to 0 U, and
this is used in the meal bolus
calculations.
Correction IOB adjustment
Correction IOB = 0.5 U
0.2 U - 0.5 U < = 0 U
Meal Bolus
0 U
You did not enter any carbs,
so you do not receive any
calculated meal bolus dose.
Carbs = 0 g, IC Ratio = 10 g/U
0/10 = 0 U
Correction IOB adjustment
Remaining correction IOB =
0.3 U
0 U - 0.3 U < = 0 U
Although there is remaining
correction IOB of 0.3 U, your
initial meal bolus is already at 0
U, so it is not adjusted further,
and your meal bolus remains
at 0 U.
Additional
Information
Effective Date: 22DEC2020, PCO-000267