Manual

Setting the Frequency of Automatic Regeneration
To determine the frequency of regeneration, use this procedure:
Total amount of iron to be removed between regenerations
÷ ppm of iron to be removed per day
= NUMBER OF DAYS BETWEEN REGENERATIONS
Example:
5 people in the household
x 60 gallons of filtered water per person
= 300 gallons of filtered water per day
x 8 ppm of iron
= 2400 PPM OF IRON TO BE REMOVED PER DAY
Using 948IF-100 + 1 Feeder
6000 ppm capacity
÷ 2400 ppm to be removed per day
=2DAYS BETWEEN REGENERATIONS
ppm of capacity between regenerations (see Specifications on Page 1)
÷ ppm of iron in the water sample*
= number of gallons supplied between regenerations
- reserve capacity (number of people x 60 gallons)
Example: Using 948IF-100 + 1 Feeder
6000 ppm between regenerations
÷ 8 ppm of iron
= 750 gallons between regenerations
- 300 gallons reserve capacity (5 people x 60 gallons)
= 450
GALLONS SETTING ON THE PROGRAM WHEEL
To obtain this setting, grasp the program wheel and, while pulling it
towards you, turn it until the number of gallons is aligned with the white
dot on the circumference. Release the dial and check for firm
engagement at setting.
* 1 ppm of manganese = 2 ppm of iron; 1 ppm of hydrogen sulfide = 3
ppm of iron
The number of gallons of filtered water your iron filter can supply between
regenerations must first be determined using the following calculations:
Upon delivery of your filter, every 4th tab in the skipper wheel is pushed outward. After determining the frequency of regeneration using
the above calculations, simply reset the skipper wheel by pulling the tabs inward on the days regeneration is not needed and pushing
the tabs outward on the days regeneration is desired. From the above example where a regeneration is required once in two days, only
every second tab on the skipper wheel should be pushed outward.
5600 MI Model
2510 MI Model
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