Reference Guide

Equation Reference 5-57
Normal Stress (14, 1)
Equations:
Example:
Given: P=40000_lbf, L=1_ft, A=3.14159265359_in^2, E=10E6_psi,
Solution: δ =0.0153_in, ∈ =0.0013, σ =12732.3954_psi.
Shear Stress (14, 2)
Equations:
Example:
Given: L=6_ft, r=2_in, J=10.4003897419_in^4, G=12000000_psi, τ =12000_psi.
Solution: T=5200.1949_ft ∗ lbf, φ =2.0626_°, γ =5.7296E–2_°.
Stress on an Element (14, 3)
Stresses and strains are positive in the directions shown.
σ
E
∈
⋅
=
∈
δ
L
-
-
-
=
σ
P
A
-
-
-
-
=
τ
G
γ
⋅
=
γ
r
φ
⋅
L
-
-
-
-
-
-
-
-
-
=
τ
T
r
⋅
J
-
-
-
-
-
-
-
-
-
-
=