Reference Guide

Equation Reference 5-29
Heat Capacity (6, 1)
Equations:
Q m c T∆⋅ ⋅= Q m c Tf Ti–( )⋅ ⋅=
Example:
Given: ∆T=15_°C, Ti=0_°C, m=10_kg, Q=25_kJ.
Solution: Tf=15_°C, c=.1667_kJ/(kg ∗ K)
Thermal Expansion (6, 2)
Equations:
Example:
Given: ∆T=15_°C, L=10_m, Tf=25_°C, δ =1_cm.
Solution: Ti=10_°C, α =6.6667E–5_1/°C.
Conduction (6, 3)
Equations:
q
k
A
⋅
L
-----------
T∆⋅= q
k A
⋅
L
-----------
Th Tc–( )⋅=
Example:
Given: Tc=25_°C, Th=75_°C, A=12.5_m^2, L=1.5_cm, k=0.12_W/ (m ∗ K)
Solution: q=5000_W, ∆T= 50_°C.
δ
α
L
T
∆
⋅
⋅
=
δ
α
L
T
f
T
i
–
(
)
⋅
⋅
=