Reference Guide
Equation Reference 5-27
Equations:
T
T
0
-
-
-
-
-
-
-
2
2
k
1
–
(
)
+
M
2
⋅
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
=
P
P
0
-
-
-
-
-
-
T
T
0
-
-
-
-
-
-
-
k
k
1
–
-
-
-
-
-
-
-
-
-
-
-
-
=
ρ
ρ
0
-
-
-
-
-
-
-
T
T
0
-
-
-
-
-
-
-
1
k
1
–
-
-
-
-
-
-
-
-
-
-
-
-
=
A
A
t
-
-
-
-
-
-
1
M
-
-
-
-
-
2
k
1
+
-
-
-
-
-
-
-
-
-
-
-
-
1
k
1
–
2
-
-
-
-
-
-
-
-
-
-
-
-
+
M
2
⋅
⋅
k
1
+
2
k
1
–
(
)
⋅
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
⋅
=
Example:
Given:
k=2, M=.9, T0=26.85_°C, T=373.15_K,
ρ
0=100_kg/m^3, P0=100_kPa, A=1_cm^2.
Solution:
P=464.1152_kPa, At=0.9928_cm^2,
ρ
=215.4333_kg/m^3.
Real Gas Law (5, 6)
These equations adapt the ideal gas law to emulate real-gas behavior. (See “ZFACTOR” in Chapter 3.)
Equations:
P V⋅ n Z R T⋅ ⋅ ⋅= m n MW⋅=
Example:
Given:
Pc=48_atm, Tc=298_K, P=5_kPa, V=10_1, MW=64_g/gmol, T=75_°C.
Solution:
n=0.0173_gmol, m=1.1057E–3_kg.
Real Gas State Change (5, 7)
This equation adapts the ideal gas state-change equation to emulate real-gas behavior. (See “ZFACTOR” in Chapter
3.)
Equation:
Pf Vf⋅
Zf Tf⋅
----------------
Pi Vi⋅
Zi Ti⋅
----------------
=
Example:
Given:
Pc=48_atm, Pi=100_kPa, Pf=50_kPa, Ti=75_°C, Tc=298_K, Vi=10_1, Tf=250_°C.
(Remember Zf and Zi are automatically calculated using these variables)
Solution:
Vf=30.1703_l.