User manual

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For example ;if there is a system with three heater ( 200V and 1kW ) ;V

In normal conditions current in heater ; [1000 / 200 ]*3 = 5A *3 = 15A

If one of the heater is out of order, there is 5*2 = 10Acurrent on two heaters. Current

in heater failure is 10A. Then Set value must be adjusted (15+10) /2 =12.5A

If a system operates with PID control form, heating minimum control time

must be minimum 0.2 second.

For correct measurements with EMI-420 ( CT) Input Module in Module-2

socket, heating output must be active minimum for 0.2 sec (200 msec).

Control Output

200VV

1kW*3

Heater

910

MODULE-2