Datasheet

M2S4G64CB88B5N / M2S8G64CB8HB5N
4GB: 512M x 64 / 8GB: 1024M x 64
PC3-10600 / PC3-12800
Unbuffered DDR3 SO-DIMM
REV 1.0 6
06/2012
© NANYA TECHNOLOGY CORPORATION
NANYA reserves the right to change products and specifications without notice.
Functional Block Diagram
[8GB 2 Ranks, 512Mx8 DDR3 SDRAMs]
DQS3

DM3
DQ[24:31]
DQS

DQ[0:7]
DM
D11
Notes :
1. DQ wiring may differ from that shown however, DQ, DM,
DQS, and relationships are maintained as shown.




CK1

CKE1
ODT1
A[0:14]/BA[0:2]
ZQ
240ohm
+/-1%




CK

CKE
ODT
A[0:14]/BA[0:2]
DQS1

DM1
DQ[8:15]
DQS0

DM0
DQ[0:7]
DQS2

DM2
DQ[16:23]
SPD
SCL
WP
SCL
SDA
SA0
SA1
A0
A1
A2
Vtt
V
REFDQ
V
REFCA
V
DD
V
DDSPD
Vtt
SPD
D0-D15
D0-D15
V
SS
D0-D15
D0-D15, SPD
CK0

CK1


D0-D7
D0-D7
D0-D15
D8-D15
D8-D15
DQS

DQ[0:7]
DM
D1
ZQ
240ohm
+/-1%




CK

CKE
ODT
DQS

DQ[0:7]
DM
D0
ZQ
240ohm
+/-1%




CK

CKE
ODT
DQS

DQ[0:7]
DM
D2
ZQ
240ohm
+/-1%




CK

CKE
ODT
DQS

DQ[0:7]
DM
D3

CK0

CKE0
ODT0
ZQ
240ohm
+/-1%




CK

CKE
ODT
DQS

DQ[0:7]
DM
D9
ZQ
240ohm
+/-1%




CK

CKE
ODT
DQS

DQ[0:7]
DM
D8
ZQ
240ohm
+/-1%




CK

CKE
ODT
DQS

DQ[0:7]
DM
D10
ZQ
240ohm
+/-1%




CK

CKE
ODT
DQS

DQ[0:7]
DM
D4
ZQ
240ohm
+/-1%




CK

CKE
ODT
DQS

DQ[0:7]
DM
D14
ZQ
240ohm
+/-1%




CK

CKE
ODT
DQS

DQ[0:7]
DM
D15
ZQ
240ohm
+/-1%




CK

CKE
ODT
DQS

DQ[0:7]
DM
D13
ZQ
240ohm
+/-1%




CK

CKE
ODT
DQS

DQ[0:7]
DM
D12
ZQ
240ohm
+/-1%




CK

CKE
ODT
DQS

DQ[0:7]
DM
D6
ZQ
240ohm
+/-1%




CK

CKE
ODT
DQS

DQ[0:7]
DM
D7
ZQ
240ohm
+/-1%




CK

CKE
ODT
DQS

DQ[0:7]
DM
D5
ZQ
240ohm
+/-1%




CK

CKE
ODT
DQS4

DM4
DQ[32:39]
DQS6

DM6
DQ[48:55]
DQS7

DM7
DQ[56:63]
DQS5

DM5
DQ[40:47]
VDD
Vtt
Cterm
Vtt
VDD
Cterm
Vtt
CKE0
CKE1


D0-D7
D8-D15
D0-D7
D8-D15
ODT0
ODT1
D0-D7
D8-D15
A[0:14]/BA[0:2]
A[0:14]/BA[0:2]
A[0:14]/BA[0:2]
A[0:14]/BA[0:2]
A[0:14]/BA[0:2]
A[0:14]/BA[0:2]
A[0:14]/BA[0:2]
A[0:14]/BA[0:2]
A[0:14]/BA[0:2]
A[0:14]/BA[0:2]
A[0:14]/BA[0:2]
A[0:14]/BA[0:2]
A[0:14]/BA[0:2]
A[0:14]/BA[0:2]
A[0:14]/BA[0:2]