User Manual

Page 59
EA Elektro-Automatik GmbH
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Germany
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ELR 9000 Series
3.8.6 Triangular function
The following parameters can be congured for a triangular wave function:
Value Range Description
I(A), U(A) 0...(Nominal value - (Off)) of U, I A = Amplitude of the signal to be generated
I(Off), U(Off) 0...(Nominal value - (A)) of U, I Off = Offset, based on the foot of the triangular wave
t1 0.1ms...36000s Time for the positive slope of the triangular wave signal.
t2 0.1ms...36000s Time for the negative slope of the triangular wave signal
Schematic diagram: Application and result:
Offset
t
A
Amplitude
t1t2
A triangular wave signal for input current (direct) or input
voltage (indirect) is generated. The positive and negative
slope times are variable and can be set independently.
The offset shifts the signal on the Y-axis.
The sum of the intervals t1 and t2 gives the cycle time
and its reciprocal is the frequency.
Example: a frequency of 10Hz is required and would lead
to periodic duration of 100ms. This 100ms can be freely
allocated to t1 and t2, e.g. 50ms:50ms (isosceles trian-
gle) or 99.9ms:0.1ms (right-angled triangle or sawtooth).
3.8.7 Rectangular function
The following parameters can be congured for a rectangular wave function:
Value Range Description
I(A), U(A) 0...(Nominal value - (Off)) of U, I A = Amplitude of the signal to be generated
I(Off), U(Off) 0...(Nominal value - (A)) of U, I Off = Offset, based on the foot of the rectangular wave
t1 0.1ms...36000s Time (pulse) of the top value (amplitude) of the rectangular wave.
t2 0.1ms...36000s Time (pause) of the base value (offset) of the rectangular wave.
Schematic diagram: Application and result:
Offset
t
A
Amplitude
t1 t2
A rectangular or square wave signal for input current
(direct) or input voltage (indirect) is generated. The
intervals t1 and t2 dene how long the value of the
amplitude (pulse) and how long the value of the offset
(pause) are effective.
The offset shifts the signal on the Y-axis
With the intervals t1 and t2 the pulse-pause relationship
(duty cycle) can be dened. The sum of t1 and t2 gives
the cycle time and its reciprocal is the frequency.
Example: a rectangular wave signal of 25Hz and a duty
cycle of 80% are required. The sum of t1 and t2, the
period, is 1/25Hz = 40ms. For a duty cycle of 80% the
pulse time (t1) is 40ms*0.8 = 32ms and the pause time
(t2) is 8ms