Manual

32 06-TTM-UM-00158 8/2012
KFACTORS EXPLAINED
The K-factor (with regards to  ow) is the number of pulses that must be accumulated to equal a particular volume of  uid. You
can think of each pulse as representing a small fraction of the totalizing unit.
An example might be a K-factor of 1000 (pulses per gallon). This means that if you were counting pulses, when the count total
reached 1000, you would have accumulated 1 Gallon of liquid. Using the same reasoning each individual pulse represents an
accumulation of 1/1000 of a gallon. This relationship is independent of the time it takes to accumulate the counts.
The frequency aspect of K-factors is a little more confusing because it also involves the  ow rate. The same K-factor number,
with a time frame added, can be converted into a  ow rate. If you accumulated 1000 counts (one gallon) in one minute, then
your  ow rate would be 1 GPM. The output frequency, in Hz, is found simply by dividing the number of counts (1000) by the
number of seconds (60) to get the output frequency.
1000 ÷ 60 = 16.6666... Hz. If you were looking at the pulse output on a frequency counter, an output frequency of 16.666...Hz
would be equal to 1 GPM. If the frequency counter registered 33.333...Hz (2 × 16.666...Hz), then the  ow rate would be 2 GPM.
Finally, if the  ow rate is 2 GPM, then the accumulation of 1000 counts would take place in 30 seconds because the  ow rate,
and hence the speed that the 1000 counts is achieved, is twice as great.
Calculating K-factors for Ultrasonic meters
Many styles of ultrasonic  ow meters are capable of measuring  ow in a wide range of pipe sizes. Because the pipe size and
volumetric units the meter will be used on vary, it is not possible to provide a discrete K-factor. Instead the velocity range of
the meter is usually provided along with a maximum frequency output.
The most basic K-factor calculation requires that an accurate  ow rate and the output frequency associated with that  ow rate
be known.
Example 1:
Known values are:
Frequency = 700 Hz
Flow Rate = 48 GPM
1) 700 Hz × 60 sec = 42,000 pulses per min
2)

42,000 min
875
48
pulses per
K factor pulses per gallon
GPM
Example 2:
Known values are:
Full Scale Flow Rate = 85 GPM
Full Scale Output Frequency = 650 Hz
1) 650 Hz x 60 sec = 39,000 pulses per min
2)

39,000 min
458.82
85
pulses per
K factor pulses per gallon
GPM