Instructions

HD2402 - 39 - V1.3
it is assumed that C
α
=100
if L
r_100
< 6
•
10
4
⇒ t_lim > 10s (j limit satisfied)
if 2.8
•
10
5
≤ L
r_100
≤ 8.89
•
10
6
⇒ t_lim = (5
•
10
5
/L
r_100
)
4
(k limit satisfied)
if L
r_100
< 8.89
•
10
6
⇒ t_lim < 10μs (l limit)
o L
r
(11mrad) [W/(m² sr)] radiance calculated assuming that all the light comes
from a circular area whose angular dimension is 11mrad. This value is to be
compared with the three limit values.
o t_
lim11
[s] exposure limit time, that is the time period during which a source can
be observed without damages to the visual system. This value is calculated with
the following procedure (all radiance values are expressed in [W m
-2
sr
-1
]):
it is assumed that C
α
= 11
if L
R_11
≤ 5.45
•
10
5
⇒ t_lim > 10s (j limit satisfied)
if 5.45
•
10
5
≤ L
R_11
≤ 8.08
•
10
7
⇒ t_lim = (4.54
•
10
6
/L
R_11
)
4
(k limit satisfied)
if L
R_11
> 8.08
•
10
7
⇒ t_lim < 10μs (l limit)
• Alpha [rad] , angular dimension of the source in radiants supplied by the user.
o Alpha [rad] angle subtended by the source.
o Omega [sr] solid angle subtended by the source, calculated starting from Alpha
angle, assuming that the source shape is circular:
Omega = 2π(1-cos(Alpha/2)
o L
R
(100mrad) [W/(m² sr)] radiance calculated assuming that the source angular
dimension is 100mrad.
o L
R
(11mrad) [W/(m² sr)] radiance calculated assuming that the source angular
dimension is 11mrad.
o L
R
(real) [W/(m² sr)] is the real radiance calculated starting from the entered
geometric parameters.
o t_lim [s] exposure limit time, that is the time period during which a source can
be observed without damages to the visual system. This value is calculated with
the following procedure (all radiance values are expressed in [W m
-2
sr
-1
]):
if Alpha > 100mrad it is assumed that C
α
= 100
if L
R_real
≤ 6
•
10
4
⇒ t > 10s (j limit satisfied)
if 6
•
10
4
≤ L
R_real
≤ 8.89
•
10
6
⇒ t_lim = (5
•
10
5
/L
R_real
)
4
[s] (k limit satisfied)
if 8.89
•
10
6
≤ L
R_real
⇒ t_lim < 10μs (l limit)
if 11mrad < Alpha < 100mrad it is assumed that C
α
= Alpha
if L
R_real
≤ 6
•
10
6
/Alpha ⇒ t > 10s (j limit satisfied)
if 6
•
10
6
/Alpha ≤ L
R_real
≤ 8.89
•
10
8
/Alpha ⇒ t_lim = (5
•
10
7
/(L
R_real
•
Alpha))
4
[s]
(k limit satisfied)
if 8.89
•
10
8
/Alpha ≤ L
R_real
⇒ t_lim < 10μs (l limit)