Technical Bulletin

Q (capacity) = 45 kW
T
con
(condensing temperature) = 25 °C
T
evap
(evaporator temperature) = -30 °C
T
sub
(subcooling temperature) =10 K
D
pd
(distributer pressure drop) = 2 bar
Q (capacity) = 45 kW
f
sub
(subcooling correction factor) = 1.09
f
p
(distributer correction factor) = 0.92
Q
= Selected capacity
f
sub
x f
p
50
= 44.9 kW
1.09 x 0.92
The selection will be:
TE 20 orice 9 (54.2 kW > 44.9 kW)
How to select a valve
Example:
SI units
Capacity in kW. Range: -40 – 10 °C.
Opening superheat sh = 4 K
SI units
R404A/R507
Valve
type
Orice
no.
Cond.
temp.
[°C]
Evap. temp. [°C]
-40 -30 -20
TE 20
8 25
35.7 48.4 62.2
9 25 39.5 54.2 71.3
TE 55
10 25
46.5 64.9 86.1
11 25 51.1 71.2 94.4
12 25
54.8 76.8 103
13 25 66.5 93.7 126
Subcooling correction factor, f
sub
Subcooling [K] 2 4 10 15
Correction factor 0,97 1,00 1,09 1,16
Distributer correction factor, f
p
SI units
R404A/R507
Pressure drop
[bar]
∆p
Evap. temp. [°C]
-40 -30 -20 -10
Correction factor
0 1 1 1 1
1 0.96 0.96 0.96 0.95
1.5 0.94 0.94 0.94 0.93
2 0.92 0.92 0.91 0.90
Calculated at 32 °C condensing temperature.
Capacity in kW. Range: -40 – 50 °F.
Opening superheat sh = 7.2 °F.
US units
R404A/R507
Valve
type
Orice
no.
Cond.
temp.
[°F]
Evap. temp. [°F]
-40 -20 0
TE 20
08 75 10.2 14.2 18.6
09 75 11.3 16.1 21.5
TE 55
10 75 13.4 19.2 26.0
11 75 14.7 21.1 28.5
12 75
15.8 22.8 31.1
13 75
19.2 27.9 38.2
Subcooling correction factor, f
sub
Subcooling [°F] 2 7 10 20
Correction factor 0.96 1.00 1.03 1.11
Distributer correction factor, f
p
US units
R404A/R507
Pressure drop
[psi]
∆p
Evap. temp. [°F]
-40 -20 0 20
Correction factor
0 1 1 1 1
15 0.96 0.96 0.96 0.95
25 0.94 0.93 0.92 0.91
30 0.92 0.92 0.91 0.89
Calculated at 90 °F condensing temperature.
Q (capacity) = 14 TR
T
con
(condensing temperature) = 75 °F
T
evap
(evaporator temperature) = -20 °F
T
sub
(subcooling temperature) = 10 °F
D
pd
(distributer pressure drop) = 30 psi
Q (capacity) = 14 TR
f
sub
(subcooling correction factor) = 1.03
f
p
(distributer correction factor) = 0.92
Q
= Selected capacity
f
sub
x f
p
14
= 14.8 TR
1.03 x 0.92
The selection will be:
TE 20 orice 9 (16.1 TR > 14.8 TR)
US units
Data sheet | Thermostatic expansion valves, type TE 5 – TE 55
© Danfoss | DCS (sw) | 2019.01
DKRCC.PD.AB0.A7.02 | 9