Manual

Triangulation Example 2
On a course of 25.25° you site a buoy and
take a bearing of 25.93°. Your second
bearing reads 74.27°. If your bearing read-
ings were taken 45 minutes apart, and you
were travelling at 25 knots, what is your
distance traveled? What is the distance
from the object and the distance Abeam?
What is the distance Abeam in feet?
Steps/Keystrokes Display
1. Clear calculator:
[On/C] [On/C] 0.
2. Enter course, then bearing 1 and 2:
25.25 [Course°]
CRSE 25.25°
25.93 [1st
Ø ] BRG 1 25.93°
74.27 [2nd
Ø ] BRG 2 74.27°
4. Enter time travelled from bearing 1 to
bearing 2:
45 [Min] [Time] TIME 45:00 MIN SEC
5. Enter speed and find distance travelled
between bearing 1 and bearing 2:
25 [Knots] [Speed] SPD 25. KNOT
[Dist] TRVL 18.75 NMI
6. Find distance from object:
[Dist] DOBJ 0.2978497 NMI
7. Find distance Abeam then convert to
feet:
[Dist]
BEAM 0.2486118 NMI
[Conv] [1] 1510.5942 FT
30 – NautiCalc Plus
™