Specifications
SELECTION PROCEDURE (With Example)
I DETERMINE THE TYPE OF FAN COIL WHICH BEST
SUITS THE APPLICATION (REFER TO SYSTEMS IN-
DEX TABLE ON PAGE 21):
Duct-free split systems have 3 types of fan coils to choose
from with overlapping capacities. Select the system type
which best meets the job conditions. This example will use
one 1
1
⁄
2
-ton high wall fan coil and one 1
1
⁄
2
ton in-ceiling
cassette.
II DETERMINE COOLING LOAD REQUIREMENTS AT DE-
SIGN CONDITIONS:
Required Load Conditions:
Required cooling capacity (TCG) .........24,000 Btuh
Sensible Heat Capacity (SHG) ...........20,000 Btuh
Temperature Air Entering
Condensing Unit ..........................95F
Temperature Air Entering
Indoor Unit (EAT) ................82Fdb/68 F wb
db — dry bulb
wb — wet bulb
III SELECT SYSTEM THAT SATISFIES LOAD
REQUIREMENTS:
Enter the Systems Index table on page 21 at systems for
24,000 Btuh, and select the system that best approximates
cooling requirements. System index no. 5 with a nominal
net capacity of 23,000 Btuh cooling is the system selected.
The system consists of a 538S024 outdoor unit matched
with one 619E018 and one 619F024 indoor unit.
IV DETERMINE IF SYSTEM SELECTED SATISFIES
COOLING REQUIREMENTS:
Enter Cooling Capacities table no. 5 on page 27 at high
speed and 95 F outdoor entering air temperature (air en-
tering condenser). By interpolation, at 68 F EAT, the sys-
tem gross capacity is 24,000 Btuh cooling [(25,600 -
23,600) × (1/5) + 23,600], and 18,460 Btuh gross sensible
capacity [(19,400 - 14,700) × (4/5) + 14,700]. Adjust the
SHG in accordance with Note 2 of the Cooling Capacity
table, using the correction factor for an 82 F edb (air en-
tering dry bulb), and an 0.17 BF (bypass factor). The result
is an adjusted SHG of 20,339 Btuh. The total gross cooling
capacity of 24,000 Btuh and the sensible heat capacity of
20,339 Btuh satisfy stipulated cooling load requirements.
V DETERMINE NET COOLING CAPACITY AND SYSTEM
ENERGY EFFICIENCY RATIO:
Determine net cooling capacity (refer to Cooling Capacity
table no. 5 on page 27). Net total cooling capacity must be
interpolated as follows:
(24,900 - 23,000) x (1/5) + 23,000 = 23,380 Btuh
To determine the energy efficiency ratio (EER), system kW
must be interpolated from Cooling Capacity table no. 5 in
the same manner:
(2.15 - 2.14) x (1/5) + 2.14 = 2.14 kW
Then calculate EER:
Net Cooling Capacity
EER =
kW x 1000
23,380
= 10.9 EER
2.14 x 1000
NOTE: The SEER (Seasonal Energy Efficiency Ratio)
CANNOT be calculated for this system. SEERs can only
be found as a direct result of testing at specified ARI con-
ditions. See ARI Capacities table on page 6.
VI DETERMINE THE RECOMMENDED VAPOR LINE
SIZES:
Refer to Refrigerant Lines section on page 40.
20