Datasheet
Table Of Contents
- Features
- Applications
- Typical Application Circuit
- General Description
- Revision History
- Functional Block Diagram
- Specifications
- Absolute Maximum Ratings
- Pin Configuration and Function Descriptions
- Typical Performance Characteristics
- Theory of Operation
- Control Scheme
- PWM Mode
- PFM Mode
- Precision Enable/Shutdown
- Separate Input Voltages
- Internal Regulator (INTVCC)
- Bootstrap Circuitry
- Low-Side Driver
- Oscillator
- Synchronization
- Soft Start
- Peak Current-Limit and Short-Circuit Protection
- Voltage Tracking
- Parallel Operation
- Power Good
- Overvoltage Protection
- Undervoltage Lockout
- Thermal Shutdown
- Applications Information
- Design Example
- External Components Recommendation
- Typical Application Circuits
- Outline Dimensions

Data Sheet ADP2323
Rev. A | Page 23 of 32
DESIGN EXAMPLE
This section explains design procedure and component selection as
shown in Figure 50; Table 11 provides a list of the required
settings.
Table 11. Dual Step-Down DC-to-DC Regulator Requirements
Parameter Specification
Channel 1
Input Voltage V
IN1
= 12.0 V ± 10%
Output Voltage V
OUT1
= 1.2 V
Output Current I
OUT1
= 3 A
Output Voltage Ripple ΔV
OUT1_RIPPLE
= 12 mV
Load Transient
±5%, 0.5 A to 3A, 1 A/µs
Channel 2
Input Voltage V
IN2
= 12.0 V ± 10%
Output Voltage V
OUT2
= 3.3 V
Output Current I
OUT2
= 3 A
Output Voltage Ripple ΔV
OUT2_RIPPLE
= 33 mV
Load Transient ±5%, 0.5 A to 3 A, 1 A/µs
Switching Frequency f
SW
= 500 kHz
OUTPUT VOLTAGE SETTING
Choose a 10 kΩ top feedback resistor (R
TOP
); calculate the bottom
feedback resistor by using the following equation:
−
×=
6.0
6.0
OUT
TOPBOT
V
RR
To set the output voltage to 1.2 V, the resistor values are R
TOP1
= 10
kΩ and R
BOT1
= 10 kΩ. To set the output voltage to 3.3 V, t h e
resistors values are R
TOP2
= 10 kΩ and R
BOT2
= 2.21 kΩ.
CURRENT-LIMIT SETTING
For 3 A output current operation, the typical peak current limit
is 4.8 A. In this case, no R
ILIM
is required.
FREQUENCY SETTING
To set the switching frequency to 500 kHz, use the following
equation to calculate the resistor value, R
OSC
:
( )
( )
kHz
000,60
kΩ
SW
OSC
f
R =
Therefore, R
OSC
=100 kΩ.
INDUCTOR SELECTION
The peak-to-peak inductor ripple current, ΔI
L
, is set to 30% of
the maximum output current. Use the following equation to
estimate the value of the inductor:
( )
SW
L
OUT
IN
fI
DVV
L
×∆
×−
=
For V
OUT1
= 1.2 V, Inductor L1 = 2.4 µH, and for V
OUT2
= 3.3 V,
Inductor L2 = 5.3 µH.
Select the standard inductor value of 2.2 µH and 4.7 µH for the
1.2 V and 3.3 V rails.
Calculate the peak-to-peak inductor ripple current as follows:
( )
SW
OUT
IN
L
fL
DVV
I
×
×−
=∆
For V
OUT1
= 1.2 V, Δ I
L1
= 0.98 A. For V
OUT2
= 3.3 V, Δ I
L2
= 1.02 A.
Find the peak inductor current by using the following equation:
2
L
OUT
PEAK
I
II
∆
+=
For the 1.2 V rail, the peak inductor current is 3.49 A, and for
the 3.3 V rail, the peak inductor current is 3.51 A.
The rms current through the inductor can be estimated by
12
2
2
L
OUT
RMS
I
II
∆
+=
The rms current of the inductor for both 1.2 V and 3.3 V is
approximately 3.01 A.
For the 1.2 V rail, select an inductor with a minimum rms
current rating of 3.01 A and a minimum saturation current
rating of 3.49 A. For the 3.3 V rail, select an inductor with a
minimum rms current rating of 3.01 A and a minimum
saturation current rating of 3.51 A.
Based on these requirements, for the 1.2 V rail, select a 2.2 µH
inductor, such as the Sumida CDRH105RNP-2R2N, with a
DCR = 7.2 mΩ; for the 3.3 V rail, select a 4.7 µH inductor, such
as the Sumida CDRH105RNP-4R7N, with a DCR = 12.3 mΩ.
OUTPUT CAPACITOR SELECTION
The output capacitor is required to meet the output voltage
ripple and load transient requirement. To meet the output
voltage ripple requirement, use the following equation to
calculate the ESR and capacitance:
RIPPLEOUT
SW
L
RIPPLEOUT
Vf
I
C
_
_
8 ∆××
∆
=
L
RIPPLEOUT
ESR
I
V
R
_
∆
=
For V
OUT1
= 1.2 V, C
OUT_RIPPLE1
= 20 µF and R
ESR1
= 12 mΩ. For
V
OUT2
= 3.3 V, C
OUT_RIPPLE2
= 7.7 µF and R
ESR2
= 32 mΩ.
To meet the ±5% overshoot and undershoot requirement, use
the following equation to calculate the capacitance:
( )
2
2
_
2
_
OUTOVOUTOUT
STEP
OV
OVOUT
VVV
LIK
C
−∆+
×∆×
=
( )
UVOUTOUT
IN
STEP
UV
UVOUT
VVV
LIK
C
_
2
_
2 ∆×−×
×∆×
=
For estimation purposes, use K
OV
= K
UV
= 2. For V
OUT1
= 1.2 V, use
C
OUT_OV1
= 191 µF and C
OUT_UV1
= 21 µF. For V
OUT2
= 3.3 V, use
C
OUT_OV2
= 54 µF and C
OUT_UV2
= 20 µF.