Specifications

DS - 2 Design Ver. 0002
Torque due to weight of the table M
w
:
When the move does not move horizontally, but at an angle "δ" like in the previous figure, the
torque due to the weight of the table must also be considered:
M
w
is the torque due to table weight and is given in Nm.
δ
is the incline angle of the ballscrew with respect to the horizontal axis.
%
is a mass compensation factor that can vary between 0 and 1.
If the total table weight is compensated for by means of some sort of hydraulic system or
counterweights so the motor makes the same effort to move the table up as to move it
down, the % factor will be "0". At the other end, if no compensation is applied, % will be
"1".
Torque to the needed cutting force
M
C
:
There is a cutting force between the tool and the part and this means a hindrance for moving
the table. The torque necessary at the motor to make this movement is calculated as follows:
M
C
is the torque due to the cutting force of the tool and is given in Nm.
F
is the cutting force of the tool and is given in Kg.
g
is the gravitational acceleration, 9.81 m/s
2
Motor speed calculation (RPM
MOTOR
).
The machine will need a maximum speed RPM
MOTOR
in a linear movement of the table.
Therefore, the motor must have a maximum speed of:
Vmax
is the maximum linear speed the table needs.
From the characteristics table for Fagor synchronous motors (chapter SM), select a motor
that has:
A Stall torque equal to or greater than the calculated continuous torque
M
S
.
A maximum turning speed equal to or greater than the calculated value,
RPM
MOTOR
M
Fgh
i
C
=
⋅⋅
2
1
π
RPM
Vmax
h
i
MOTOR
=⋅
M
mgsin h
i
W
=
⋅⋅
δ
π
2
%