Product specifications

Instrumentation Laboratory Exercise 50
To obtain the period you must wire up the User Objects to the
incoming array, the UT, and feed the first index (from the object
named 1st Transit) value into the second User Object (called 2nd Transit).
The value needs to be incremented first by running it through a
formula box which simply calculates A+1 as its result.
Finally, the period is converted to rpm. There are eight holes, so each
cycle is 1/8 of a revolution. Reading at 80,000 Hz means that the
period of a revolution is eight times our period (B- A) divided by
80,000. The frequency (in Hz) of the revolution is then 80,000 / (8 ×
(B - A)), or simply 10,000 / (B - A). The speed in rpm is 60 times
this number.
Now that you have the period, convert it to actual speed in rpm.
Recall that rpm is equal to the speed in Hz times 60. Display motor
torque (current) as a function of motor speed in an X vs Y Plot (under
Display menu). Notice you can right clock this display and erase it at
any time, creating a clear motor speed- torque curve: